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Find the first order partial derivatives of f(x,y)=y^5-3xy |
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Answer» so here is your answer with details Step-by-step explanation: Question: Find the first-order partial derivatives of the GIVEN function. ( x , y ) = y 5 − 3 x y Partial derivatives: To evaluate partial derivative of a function h ( x , y ) with respect to x , keep y as FIXED number and evaluate derivative with respect to x . Similarly, to evaluate partial derivative of a function h ( x , y ) with respect to y , keep x as fixed number and evaluate derivative with respect to y . Answer and Explanation: Given The given function is f ( x , y ) = y 5 − 3 x y . Solution Partial differentiate the function f ( x , y ) = y 5 − 3 x y with respect to x . ∂ f ∂ x = ∂ ∂ x [ y 5 − 3 x y ] = − 3 y Partial differentiate the function f ( x , y ) = y 5 − 3 x y with respect to y . ∂ f ∂ y = ∂ ∂ y [ y 5 − 3 x y ] = 5 y 5 − 1 − 3 x = 5 y 4 − 3 x Therefore, ∂ f ∂ x = − 3 y and ∂ f ∂ y = 5 y 4 − 3 x |
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