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Find the first term of a HP whpse secpmd ter, os `(5)/(4)` and the third term is `(1)/(2)`. |
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Answer» Let a be the first term. Then, `a,(5)/(4),(1)/(2)` are in HP. Then, `(a-(5)/(4))/((5)/(4)-(1)/(2))=(a)/((1)/(2)) " " [" from above note "]` ` implies (4a-5)/(5-2)=2a` ` implies 4a-5=6a " or " 2a=-5` ` therefore a=-(5)/(2)` |
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