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Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10^-4 N,(a) 8.15(b) 5.18(c) 1.518(d) 1.815The question was asked in my homework.I need to ask this question from Coulomb Law in portion Electrostatic Fields of Electromagnetic Theory

Answer» RIGHT OPTION is (d) 1.815

The explanation: 1 stat COULOMB = 1/(3 X 10^9) C

F = (1.998 X 1.2488 X 10^-16)/(4∏ X 8.854 X 10^-12 X 2.2 X (7.5 X 10^-2)^2) = 1.815 X 10^-4 N.


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