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Find the fourth vertex of the parallelogram whose three consecutive vertices are (8,8) , (6,1) and (-1,1) . |
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Answer» Let the three vertices of the parallelogram be A(8,8) , B(6,1) and C(-1,1) , then fourth vertex D( x, y) is given by `D(x , y) = (x_(1) - x_(2) + x_(3) , y_(1) - y_(2) + y_(3))` `= ( 8 - 6 - 1 , 8 - 1 + 1)` = `(1,8)` . Hence , the fourth vertex is D(1,8) . |
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