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Find the general solution of `(1-2 cos theta)^(2)+(tan theta +sqrt(3))^(2)=0`. |
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Answer» Correct Answer - `theta=2n pi+(5 pi)/3, n in Z` `(1-2 cos theta)^(2)+(tan theta +sqrt(3))^(2)=0` `rArr (1-2 cos theta)^(2)=0` and `(tan theta +sqrt(3))^(2)=0` `rArr cos theta=1/2` and `tan theta=-sqrt(3)` Hence, `theta` is in the fourth quadrant, and `theta=2pi-pi/3=(5pi)/3` Hence, the general solution is `theta=2 npi+(5pi)/3, n in Z`. |
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