1.

Find the general solution of the differential equations:`(dx)/(dy)+y/x=x^2`

Answer» In this question,
`P = 1/x and Q = x^2`
Now, we have to compute integrating factor(I.F.).
We know,
`I.F. = e^(intPdx)`,so,
`I.F. = e^(int(1/x)dx) = e^lnx=x`
So, solution will be
`y*(I.F.) = int(I.F.)Qdx`
`yx = intx*x^2dx`
`yx = intx^3dx`
`yx=x^4/4+c`
`y = x^3/4+c/x` that is the general solution.


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