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Find the general solution of the differential equations:`(dx)/(dy)+y/x=x^2` |
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Answer» In this question, `P = 1/x and Q = x^2` Now, we have to compute integrating factor(I.F.). We know, `I.F. = e^(intPdx)`,so, `I.F. = e^(int(1/x)dx) = e^lnx=x` So, solution will be `y*(I.F.) = int(I.F.)Qdx` `yx = intx*x^2dx` `yx = intx^3dx` `yx=x^4/4+c` `y = x^3/4+c/x` that is the general solution. |
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