1.

Find the general solution of the trignometric equation `3^(1/2+log_(3)(cosx+sinx))-2^(log_(2)(cosx-sinx))=sqrt(2)`A. `2n pi+(5pi)/(4)`B. `n pi-(pi)/(4)`C. `n pi+(-1)^(n)(pi)/(4)`D. `2n pi+(pi)/(4)`

Answer» Correct Answer - A
`because A.M. ge G.M. therefore (2^(sin x)+2^(cos x))/(2)ge sqrt(2^(sin x).2^(cos x))`
`therefore 2^(sin x)+2^(cos x)ge 2. sqrt(2^(sin x + cos x))`
But minimum value of cos x + sin x is `- sqrt(2)`
`thereofre 2^(sin x)+2^(cos x)ge 2. sqrt(2^(-sqrt(2)))=2^(1-(1)/(sqrt(2)))`
But the given equation is `2^(sin x)+2^(cos x)=2^(1-(1)/(sqrt(2)))`, which can hold only if `2^(sin x)=2^(cos x)=2^(-(1)/(sqrt(2)))`
`rArr x = 2n pi + (5pi)/(4), n in Z`


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