1.

Find the general value of `theta` from the equaion `sqrt(3)sintheta+costheta=1`

Answer» `sqrt(3)sintheta+costheta=1`
Divide both sides by `sqrt((sqrt(3))^(2)+1^(2))=2`
`sqrt(3)/2sintheta+1/2costheta=1/2`
`rArr sinpi/3sintheta+cospi/3= cospi/3`
`rArr cos(theta-pi/3)=cospi/3`
`rArr theta-pi/3=2npi+-pi/3`
`rArr theta=2npi+-pi/3+pi/3`
`rArr theta=2npi+(2pi)/(3)` or `theta=2npi`. Ans.


Discussion

No Comment Found

Related InterviewSolutions