1.

Find the gratest number which divide615 and963 leaving the remainder 6 in each case​

Answer»

Answer:

87

Step-by-step explanation:

615 - 6 = 609

963 - 6 = 957 (because it leaves a REMAINDER 6)

FACTORS of:-

609 = 3 x 7 x 29

957 = 3 x 11 x 29

HCF (609, 957) = 3 x 29 = 87

Therefore the gratest number which divide 615 and 963 leaving the remainder 6 is 87.



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