Find the greatest no. that will divide 455 , 582 and 710 leaving remai

1.	Find the greatest no. that will divide 455 , 582 and 710 leaving remainders 14 , 15, 17
Answer» Answer: Given numbers are 455, 582 and 710 and the RESPECTIVE REMAINDERS are 14, 15 and 17. We have 455 – 14 = 441, 582 – 15 = 567 and 710 – 17 = 693. Now let us find their HCF. Playing With Numbers Class 6 Extra Questions Maths Chapter 3 Common factors are 3 and 7. ∴ HCF = 3 x 7 = 21 Hence, the required NUMBER is 21.

Find the greatest no. that will divide 455 , 582 and 710 leaving remainders 14 , 15, 17

Answer»

Answer:

Given numbers are 455, 582 and 710 and the RESPECTIVE REMAINDERS are 14, 15 and 17.

We have 455 – 14 = 441, 582 – 15 = 567 and 710 – 17 = 693.

Now let us find their HCF.

Playing With Numbers Class 6 Extra Questions Maths Chapter 3

Common factors are 3 and 7.

∴ HCF = 3 x 7 = 21

Hence, the required NUMBER is 21.