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Find the greatest no. which divides 82 and 132 leaving 1 and 6 respectively as remainder. solve with full process |
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Answer» : 9 is the greatest no. which divides 82 and 132 leaving 1 and 6 RESPECTIVELY as remainder. In order to find the greatest number, we've to find the H.C.F of ( 82 - 1 ) and ( 132 - 6 ) 82 - 1 = 81 132 - 6 = 126 Now, → 81 = 3 × 3 × 3 × 3 → 126 = 3 × 3 × 2 × 7 ∴ H.C.F = 3 × 3 = 9 Hence, 9 is the greatest no. that divides 81 and 132. |
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