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Find the greatest number of four digits which is exactly divisible by 15, 24 and 36. |
Answer» The greatest four digit number = 9999 We can get the required number by following steps: Step 1: Divide 9999 by LCM of 15, 24 and 36 Step 2: Subtract result of Step 1 from 9999. Prime factorization: 15 = 3 × 5 24 = 23 × 3 36 = 22 × 32 LCM(15, 24, 36) = 23 × 32 × 5 = 360 Step 1: Dividing 9999 by 360, we get 279 as remainder. Step 2: Subtract 279 from 9999 9999 – 279 = 9720 The greatest number of four digits which is exactly divisible by 15, 24 and 36 is 9720. |
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