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Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. |
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Answer» Given numbers are 43, 91 and 183. Subtract smallest number from both the highest numbers. we have three cases: 183 > 43; 183 > 91 and 91 > 43 183 – 43 = 140 183 – 91 = 92 and 91 – 43 = 48 Now, we have three new numbers: 140, 48 and 92. Find HCF of 140, 48 and 92 using prime factorization method, we get HCF (140, 48 and 92) = 4 The highest number that divide 183, 91 and 43 and leave the same remainder is 4. |
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