Saved Bookmarks
| 1. |
Find the greatest number which divide 615 and 963, leaving the remainder 6 in each case |
|
Answer» 87Step-by-step EXPLANATION:To find the largest number which DIVIDES 615 and 963 leaving remainder 6 in each CASE i.e. HCF. Consider HCF be x. In ORDER to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases. 609 = 3 x 3 x 29 957= 3 x 11 x 29 ⇒ x = 3 x 29 = 87 ∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87. |
|