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Find the greatest number which divides 203 and 434 leaving reminder 5 in each case.. Plz can you send me picture of the answer i will mark you as a brainlist |
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Answer» 33Step-by-step explanation: Given that the NUMBERS 203 and 434 leaving remainder 5 in each case respectively. The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429. Prime factorization of 198 = 2 * 3 * 3 * 11 Prime factorization of 429 = 3 * 11 * 13. HCF(198,429) = 3 * 11 = 33.Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33. |
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