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Find the greatest number which when divided by 20, 25, 35 and 40 leaves remainder as 14 , 19, 29 and 34 respectively. |
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Answer» First LCM of 20, 25, 35 and 40, using prime factorization method 20 = 2×2×5 25 = 5×5 35 = 5×7 40 = 2 x 2×2×5 LCM (20,25,35, 40) = 1400 As per given statement, we have to find the greatest number which when divided by 20, 25, 35 and 40 leaves remainder as 14 , 19, 29 and 34 respectively i.e. 6 less than the divisor in each case. Required number = 1400 – 6 = 1394 1394 is the required number. |
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