1.

Find the H.C.F. by long division method are 90 35​

Answer»

95 = 35 x 2 + 25

35 = 25 x 1 + 10 (divisor of PREVIOUS step BECOMES DIVIDEND of new step and remainder of previous step becomes divisor of new step)

25 = 10 x 2 + 5

10 = 5 x 2 + 0 (stop when remainder is 0)

The previous remainder is the HCF

Hence, the required HCF is 5


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