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Find the H.C.F of 2x square-8,2x+4. Plz fast it’s aurgent

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Answer:

2x²-x-1 = 2x²-2X+1x-1

= 2x(x-1)+1(x-1)

= (x-1)(2x+1)

4x²+8x+3 = 4x²+2x+6x+3

=2x(2x+1)+3(2x+1)

(2x+1)(2x+3)

HCF is (2x+1)

LCM is (x-1)(2x+1)(2x+3)



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