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Find the HCF of 48,36,24 by prime factorisation |
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Answer» Answer: step 1 Address the method, input PARAMETERS & values Integers: 24, 36, 48 find gcf (24, 36 and 48) = ? step 2 Find the prime factors of all integers of the GROUP 24 = 2 x 2 x 2 x 3 36 = 2 x 2 x 3 x 3 48 = 2 x 2 x 2 x 2 x 3 step 3 The COMMON prime factor or the product of all common prime factors between all integers is the highest common factor of this group of integers (24, 36 & 48). HCF(24, 36, 48) = 12 |
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