1.

Find the HCF of the pair of integers and express it as a linear combination of them 693 and 657.

Answer»

By applying Euclid’s division lemma on 963 and 657, we get 

963 = 657 x 1 + 306………. (1) 

As the remainder ≠ 0, apply division lemma on divisor 657 and remainder 306 

657 = 306 x 2 + 45………… (2) 

As the remainder ≠ 0, apply division lemma on divisor 306 and remainder 45 

306 = 45 x 6 + 36…………. (3) 

As the remainder ≠ 0, apply division lemma on divisor 45 and remainder 36 

45 = 36 x 1 + 9…………… (4) 

As the remainder ≠ 0, apply division lemma on divisor 36 and remainder 9 

36 = 9 x 4 + 0……………. (5) 

Thus, we can conclude the H.C.F. = 9. 

Now, in order to express the found HCF as a linear combination of 963 and 657, we perform 

9 = 45 – 36 x 1 [from (5)] 

= 45 – [306 – 45 x 6] x 1 

= 45 – 306 x 1 + 45 x 6 [from (3)] 

= 45 x 7 – 306 x 1 

= [657 -306 x 2] x 7 – 306 x 1 [from (2)] 

= 657 x 7 – 306 x 14 – 306 x 1 

= 657 x 7 – 306 x 15 

= 657 x 7 – [963 – 657 x 1] x 15 [from (1)] 

= 657 x 7 – 963 x 15 + 657 x 15 

= 657 x 22 – 963 x 15.



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