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Find the HCF of the pairs of numbers 56 and 88. |
Answer» Now, apply Euclid’s Division lemma on 56 and 88 88 = 56 x 1 + 32. Since remainder ≠ 0, apply division lemma on 56 and remainder 32 56 = 32 x 1 + 24. Since remainder ≠ 0, apply division lemma on 32 and remainder 24 32 = 24 x 1 + 8. Since remainder ≠ 0, apply division lemma on 24 and remainder 8 24 = 8 x 3 + 0. Therefore, H.C.F. of 56 and 88 is 8. |
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