1.

Find the heat change in the reaction : NH_(3)(g)+HCl(g)rarr NH_(4)Cl(s) from the following data {:(NH_(3)(g)+aq rarr NH_(3)(aq)",",Delta H=-8.4"K. Cal."),(HCl(g)+aq rarr HCl (aq)",",Delta H=-17.3"K. Cal."),(NH_(3)(aq)+HCl(aq)rarrNH_(4)Cl(aq)",",Delta H=-12.5 "K. Cals."),(NH_(4)Cl(s)+aq rarr NH_(4)Cl(aq)",",Delta H=+3.9 "K.Cal."):}

Answer»

`-42.1`
`-34.3`
`+34.3`
`+42.1`

Solution :`NH_(3(G))+HCl_((g))rarr NH_(4)Cl_((s)), Delta H = ?`
DESIRED EQUATION= EQ(i) + eq(ii) + eq(iii) - eq(iv)
`Delta H=(-8.4)+(-17.3)+(-12.5)-(3.9)`
`Delta H =-42.1 KCal`


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