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Find the height from which body of a mass 50kg should fall in order to have the K.E of a car of mass 200kg travelling at 10ms-1 Given g = 9.8ms-2. |
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Answer» Mass of a body, m1 = 50 kg Mass of car m2 = 200kg velocity of the car v = 10ms-1 g = 9.8ms-2 P.E of the body, P.E = mgh = 50 × 9.8 × h = 490h K.E of the car K.E = \(\frac{1}{2}\)m2v2 \(\frac{1}{2}\)× 200 × 102 = 10,000J But P.E of body = K.E of car 490h = 10,000 h = \(\frac{10,000}{490}\) = 20.41 m. |
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