1.

Find the height of a right angle of area 106 cm sq. and base 20 cm.​

Answer»

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area \: \: \: of \: \: \: a \: \: \: triangle \: \: \: = \: \: \: \frac{1}{2} \times b \times h \\ \\ 106 = \frac{1}{2} \times 20 \times h \\ \\ \frac{106 \times 2}{20} = h \\ \\ 10.6 = h

\huge{\red{\boxed{\orange{h = 10.6}}}}


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