1.

Find the height of projectile 4 seconds after it is launched?

Answer»

Answer:

CORRECT option is

A

98m

Time of flight=4+5=9 s

so,

G

2usinθ

=9

or usinθ=

2

9g

if H is the height of P, then

h=(usinθ)4−

2

1

g(4)

2

=

2

9g

×4−

2

1

g×16

=10g=98m

hence,option Ais correct.

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