Find the height of the cylinder whose base radius is 17cm and total su

1.	Find the height of the cylinder whose base radius is 17cm and total surface area is 1936sq. cm
Answer» Diagram : $\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{r}}\put(9,17.5){\sf{h}}\end{picture}$ Given:- In a CYLINDER TSA= $\bf {1936\:cm^2}$ Radius (r) =17cm To find : HEIGHT (h). SOLUTION : As we KNOW that in a Cylinder : ${\boxed{\bf TSA=2 {\pi}r (h+r)}}$ Substitute the values : $\longrightarrow\sf 2 \times {\dfrac {22}{7}} \times 17(h+17)=1936 \\ \\$ $\longrightarrow\sf {\dfrac {748}{7}} \times(h + 17)=1936 \\ \\$ $\longrightarrow\sf h + 17=1936 \div \dfrac{748}{7} \\ \\$ $\longrightarrow\sf h + 17= \cancel{1936}\times \dfrac{7}{ \cancel{748}} \\ \\$ $\longrightarrow \sf h + 17= \dfrac {3388}{187} \\ \\$ $\longrightarrow\sf h= \dfrac{3388}{187} - 17 \\ \\$ $\longrightarrow\sf h= \dfrac{3388 - 3179}{187} \\ \\$ $\longrightarrow\sf h= \dfrac{209}{187} \\ \\$ $\longrightarrow{\boxed{\green{\bf{ h= 1.12 \:cm}}}} \\ \\$

Find the height of the cylinder whose base radius is 17cm and total surface area is 1936sq. cm

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Diagram :

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{r}}\put(9,17.5){\sf{h}}\end{picture}$