InterviewSolution
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InterviewSolution
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Find the (i) angular momentuum (ii) velocity of the electron in the 5^(th) orbit of hydrogen atom (h = 66 xx 10^(-34) Js, m = 9.1 xx 10^(-31) kg) |
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Answer» SOLUTION :(i) Angular momentum is given by `l = nh = (nh)/(2 pi)` `= (5 XX 6.6 xx 10^(-34))/(2 xx 3.14) = 5.25 xx 10^(-34) kgm^(2)s^(-1)` (II) Velocity is given by `Velocity v = (l)/(mr)` ` = ((5.25 xx 10^(-34) kgm^(2)s^(-1)))/((9.1 xx 10^(-31) kg)(13.25 xx 10^(-10) m))` `v = 4.4 xx 10^(5) ms^(-1)` |
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