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Find the (i) Net elongation rod approximately. `(x xx 10^(-11)m)` then `x =` (ii) `Y_(eq)` of the composite rod `(x xx 0^(11) N..m^(2))` (assume `A` = area of cross section of each rod),. Then `x =` `l_(1) = l(2) = 1m, F = 2N//m^(2), A = 1sq.m^(2)` `y_(1) = 2xx10^(11) N//m^(2)n, y_(2) = 3xx10^(11) N//m^(2)` ltbr4gt |
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Answer» Correct Answer - (i) 2 (i) `(F)/(A) ((l_(1))/(y_(1)) + (l_(2))/(y_(2)))`, (ii) `(y_(1) y_(2)(l_(1) + l_(2)))/(l_(1) y_(2) + l_(2) y_(1))` (i) `1.67xx10^(-11)m`, (ii) `2.4xx10^(-11) N//m^(2)` |
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