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Find the image of the point `(-sqrt2,sqrt2)` by the line mirror` y=x tan ((pi)/(8)).` |
Answer» Let`(x_(1),y_(1))` be the image of `(-sqrt2,sqrt2)` about the line `y=xtan((pi)/(8)).` On comparing `y=x tan ((pi)/(8)) by y = x tan theta` ` therefore" " theta=(pi)/(8)` Now, `[(,x_(1)),(,y_(1))]=[(cos2theta,sin2theta),(sin2theta,-cos2theta)][(,-sqrt2),(,sqrt2)]` `[((1)/sqrt2,(1)/sqrt2),((1)/sqrt2,(1)/sqrt2)][(,-sqrt2),(,sqrt2)]=[(,0),(,-2)]` On comparing `x_(1)=0 and y_(1)=-2` therefore, the requried image is `(0,-2)` |
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