1.

Find the incentre of the triangle with vertices `(1, sqrt3), (0, 0)` and `(2, 0)`

Answer» Correct Answer - `(1,(1)/(sqrt3))`
Here `AB=BC=CA=2`
So, it is an equilateral triangle and the incentre coincides with centroid.
Therefore, centroid
`((0+1+2)/(3),(0+0+sqrt3)/(3))-=(1,(1)/sqrt3)`


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