Find the intercepts cut off by the plane `2x + y z = 5`. – InterviewSolution

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1.	Find the intercepts cut off by the plane `2x + y z = 5`.
Answer» Given plane `2x+y-z=5` can be written as : `(2x)/(5) + (y)/(5) - z/5 = 1` `rArr (x)/(5//2) + y/5 + (z)/(-5) = 1` Here, `a = 5/2 , b = 5` and `c = - 5` Thereform, intercepts are `5/2,5` and `-5`

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