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Find the kinetic energy, potential energy and total energy in first and second orbit of hydrogen atom if potential energy in first orbit is taken to be zero. |
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Answer» SOLUTION :`E_(1)=-13.60eV,K_(1)=-E_(1)=13.60eV` `U_(1)=2E_(1)=-27.20eV` `E_(2)=-3.40eV""K_(2)=3.40eV` and `U_(2)=-6.80eV` Now, `U_(1)=0`, i.e., potential energy has been INCREASED by 27.20eV. So, we willincrease U and E in all energy states by 27.20eV while kinetic energy will remain unchanged. Hence `K(eV),U(eV),E_(eV)` FIRST orbit are 13.6, 0, 13.6 in SECOND orbit 3.40, 20.40, 23.80 |
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