InterviewSolution
Saved Bookmarks
| 1. |
Find The Largest Number, Smaller Than The Smallest Four-digit Number, Which When Divided By 4,5,6and 7 Leaves A Remainder 2 In Each Case? |
|
Answer» TAKE LCM of 4,5,6,7. It is 420 BUt the no must leave remainder 2 in each case, so the no is of the form: 420k + 2. The SMALLEST 4-DIGIT no is 1000. So keeping k=0,1,2,3. We get that the largest no smaller than the smallest 4 -digit no is 842. Take LCM of 4,5,6,7. It is 420 BUt the no must leave remainder 2 in each case, so the no is of the form: 420k + 2. The smallest 4-digit no is 1000. So keeping k=0,1,2,3. We get that the largest no smaller than the smallest 4 -digit no is 842. |
|