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Find the largest number which divides 438 and 606 leaving remainder 6 in each case. |
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Answer» Largest number which divides 438 and 606, leaving remainder 6 is actually the largest number which divides 438 – 6 = 432 and 606 – 6 = 600, leaving remainder 0. Therefore, HCF of 432 and 600 gives the largest number. Now, prime factors of 432 and 600 are: 432 = 24 × 33 600 = 23 × 3 × 52 HCF = product of smallest power of each common prime factor in the numbers = 23 × 3 = 24 Thus, the largest number which divides 438 and 606, leaving remainder 6 is 24. |
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