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Find the largest number which divides 438 and 606, leaving remainder 6 in each case. |
Answer» The largest number divides 438 and 606, leaving remainder 6 is the largest number divides 432 (i.e. 438 – 6 = 432) and 600 (i.e. 606 – 6 = 600) HCF of 432 and 600 gives the required number. To find: HCF of 432 and 600 Find HCF of 432 and 600 using prime factorization 432 = 24 × 33 600 = 23 × 3 × 52 HCF = 23 × 3 = 24 Therefore, the required number is 24. |
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