1.

Find the largest number which divides 438 and 606, leaving remainder 6 in each case.

Answer»

The largest number divides 438 and 606, leaving remainder 6 is the largest number divides 432 (i.e. 438 – 6 = 432) and 600 (i.e. 606 – 6 = 600)

HCF of 432 and 600 gives the required number.

To find: HCF of 432 and 600

Find HCF of 432 and 600 using prime factorization

432 = 24 × 33

600 = 23 × 3 × 52

HCF = 23 × 3 = 24

Therefore, the required number is 24.



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