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Find the last three digits of the number `27^(27)dot` |
Answer» Correct Answer - Last three digits are 803 `27^(27) = 3(10-1)^(40)` `= 3(10^(40) - .^(40)C_(1) .10^(39) +"….." + .^(40)C_(38).10^(2)-.^(40)C_(39).10+1)` `= (1000 lambda - 400 + 1)` `= 3(1000 lambda - 399)` Therefore, last 3 digits of this number of `803`. |
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