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Find the least number which when divided by 33, 44, and 55 leaves remainders 31, 42 and 53respectively. |
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Answer» Answer: HENCE, \(658\) is the smallest number when DIVIDED by \(33,\;44\;\text{and}\;55\)leaves remainders \(\;31,\;42\;\text{and}\;53\), RESPECTIVELY. |
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