InterviewSolution
Saved Bookmarks
| 1. |
Find the least number which when divided by 35, 56 and 91 leaves the same remainder 7 in each case. |
|
Answer» The required number is determine with the help of LCM of 35, 56 and 91. Using prime factorization, find the LCM: 35 = 5 x 7 56 = 2 x 2 x 2 x 7 91 = 7 x 13 LCM (35, 56 and 91) = 23 x 5 x 7 x 13 = 3640 Least number which when divided by 35, 56 and 91 leaves the same remainder 7 is 3640 + 7 = 3647. |
|