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Find The Least Number Which When Divided By 35 And 11 Leaves A Remainder Of 1 In Each Case. |
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Answer» The LEAST number which when divided by different divisors leaving the same remainder in each case = LCM(different divisors) + remainder left in each case. HENCE the required least number = LCM(35, 11) + 1 = 386. The least number which when divided by different divisors leaving the same remainder in each case = LCM(different divisors) + remainder left in each case. Hence the required least number = LCM(35, 11) + 1 = 386. |
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