1.

Find The Least Number Which When Divided By 35 And 11 Leaves A Remainder Of 1 In Each Case.

Answer»

The LEAST number which when divided by different divisors leaving the same remainder in each case

= LCM(different divisors) + remainder left in each case.

HENCE the required least number 

= LCM(35, 11) + 1 = 386.

The least number which when divided by different divisors leaving the same remainder in each case

= LCM(different divisors) + remainder left in each case.

Hence the required least number 

= LCM(35, 11) + 1 = 386.



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