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Three Fair Coins Are Tossed. What Is The Probability Of Getting At Most Two Heads ?

Answer»

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH} 

Let E = occasion of GETTING at most two heads. 

At that point E = {TTT, TTH, THT, HTT, THH, HTH, HHT}. 

P (E) = N (E)/n(S) = 7/8

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH} 

Let E = occasion of getting at most two heads. 

At that point E = {TTT, TTH, THT, HTT, THH, HTH, HHT}. 

P (E) = n (E)/n(S) = 7/8


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