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Find the least number which when divided by 40, 50 and 60 leavesremainder 5 in each case. |
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Answer» Answer: 605 Step-by-step explanation: Smallest common multiple of 40, 50 and 60 = L.C.M of 40, 50, 60 = 600 Since, we have to FIND the NUMBER when DIVIDED by 40,50,60 leaves the remainder 5 we have add 5 to 600. 600+5 = 605 |
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