Find the least number which when divided by 6, 15 and 18 leaves remain

1.	Find the least number which when divided by 6, 15 and 18 leaves remainder 5 in each case.
Answer» <html><body><p>-step explanation:6 = 2 × 315 = 3 × 518 = 2 × 3 × 3L.C.M of 6, <a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> and <a href="https://interviewquestions.tuteehub.com/tag/18-278913" style="font-weight:bold;" target="_blank" title="Click to know more about 18">18</a> = 2 x 3 x 3 x 5L.C.M (6, 15 and 18) = 90Therefore, the required number = 90+5 = 95As a result, 95 is the <a href="https://interviewquestions.tuteehub.com/tag/smallest-646176" style="font-weight:bold;" target="_blank" title="Click to know more about SMALLEST">SMALLEST</a> number, with a remainder of 5 in each case when <a href="https://interviewquestions.tuteehub.com/tag/divided-441039" style="font-weight:bold;" target="_blank" title="Click to know more about DIVIDED">DIVIDED</a> by 6, 15, and 18.As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.</p></body></html>

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