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Find the least number which when divided by 6, 15 and 18 leaves remainder 5 in each case. |
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Answer» -step explanation:6 = 2 × 315 = 3 × 518 = 2 × 3 × 3L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5L.C.M (6, 15 and 18) = 90Therefore, the required number = 90+5 = 95As a result, 95 is the SMALLEST number, with a remainder of 5 in each case when DIVIDED by 6, 15, and 18.As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18. |
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