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Find the least number which when divides 35, 56 and 91 leaves the same remainder 7 in each case. |
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Answer» Least number which can be divided by 35, 56 and 91 is LCM of 35, 56 and 91. Prime factorization of 35, 56 and 91 is: 35 = 5 × 7 56 = 23 × 7 91 = 7 × 13 LCM = product of greatest power of each prime factor involved in the numbers = 23 × 5 × 7 × 13 = 3640 Least number which can be divided by 35, 56 and 91 is 3640. Least number which when divided by 35, 56 and 91 leaves the same remainder 7 is 3640 + 7 = 3647. Thus, the required number is 3647. |
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