1.

Find the least number which when divides 35, 56 and 91 leaves the same remainder 7 in each case.

Answer»

Least number which can be divided by 35, 56 and 91 is LCM of 35, 56 and 91. 

Prime factorization of 35, 56 and 91 is: 

35 = 5 × 7 

56 = 23 × 7 

91 = 7 × 13 

LCM = product of greatest power of each prime factor involved in the numbers = 23 × 5 × 7 × 13 = 3640 

Least number which can be divided by 35, 56 and 91 is 3640. 

Least number which when divided by 35, 56 and 91 leaves the same remainder 7 is 3640 + 7 = 3647.

Thus, the required number is 3647.



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