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Find the length of an arc of a circle of radius 5 cm subtending a central angle measuring 15°. |
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Answer» Let s be the length of the arc subtending an angle θc at the center of a circle of radius r. Then, θ = \(\frac{s}{r}\) Here, r = 5 and θ = 15° = \((15\times\frac{\pi}{180})^c\) = \((\frac{\pi}{12})^c\) θ = \(\frac{s}{r}\) ⇒ \(\frac{\pi}{12}=\frac{s}{5}\) ⇒ s = \(\frac{5\pi}{12}\) cm |
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