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Find the linear inequalities for which the shaded region in the given figure is the solution set. |
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Answer» Consider the line ` 3x+ 2y=48`, we observe that the shaded and the origin are on the same side of the line ` 3x+2y=48 and (0,0)` satisfy the linear constraint ` 3x+2y le 48`. So, we must have one inequation as ` 3x+2 y le 48`. Now, condider the line x+ y = 20 . We find that the shaded region and the origin are on the same side of the line x + y = 20 and (0, 0) satisfy the constraints ` x+y le 20`. So, the second inequation is ` x + y le 20`. We also notice that the shaded region is above X- axis and is on the right side of y-axis, so we must have ` x ge 0, y ge 0`. Thus, the linear inequations corresponding to the given solution set are `3x + 2 y le 48, x + y le 20 and x ge 0, y ge 0`. |
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