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Find the locus of the point of intersection of the perpendiculartangents of the curve `y^2+4y-6x-2=0`. |
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Answer» Correct Answer - 2x+5=0 We know that perpendicular tangents meet at the directrix. The given parabola is `y^(2)+4y-4x-2=0` `or" "(y+2)^(2)=6(x+1)` The equation of directrix is `x+1=-(6)/(4)orx=-(5)/(2)` `or" "2x+5=0` |
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