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Find the Lorentz force due to a conductor of length 2m carrying a current of 1.5A and magnetic flux density of 12 units.(a) 24(b) 36(c) 32(d) 45I got this question during an online interview.Question is from Magnetization topic in division Magnetic Forces and Materials of Electromagnetic Theory

Answer»

The correct answer is (b) 36

Easy explanation: The Lorentz is GIVEN by the product of the current, DIFFERENTIAL length and the magnetic flux density. Put B = 12, I = 1.5 and L = 2, thus we get F = BIL = 12 x 1.5 x 2 = 36 units.



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