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Find the magnetic field intensity due to a solenoid of length 12cm having 30 turns and current of 1.5A.(a) 250(b) 325(c) 175(d) 375The question was asked in an interview for job.The query is from Magnetic Field Intensity topic in section Magnetostics of Electromagnetic Theory

Answer» RIGHT option is (d) 375

Easiest explanation: The magnetic field intensity of a SOLENOID is GIVEN by H = NI/L = 30 X 1.5/0.12 = 375 units.


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