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Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A.(a) 103.45(b) 102(c) 105.7(d) 171This question was posed to me by my college director while I was bunking the class.My enquiry is from Magnetic Field Intensity topic in division Magnetostics of Electromagnetic Theory

Answer»

Correct OPTION is (a) 103.45

To explain: The MAGNETIC FIELD intensity of a toroid is given by H = NI/2πrm. Put N = 40, I = 3.25 and RM = 0.2, we get H = 40 x 3.25/2π x 0.2 = 103.45 units.



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