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Find the magnetic flux density of a finite length conductor of radius 12cm and current 3A in air( in 10^-6 order)(a) 4(b) 5(c) 6(d) 7The question was asked in my homework.I want to ask this question from Ampere Law in section Magnetostics of Electromagnetic Theory

Answer»

The correct option is (b) 5

Explanation: The MAGNETIC field intensity is given by H = I/2πr, where I = 3A and R = 0.12. The magnetic flux DENSITY in AIR B = μ H, where μ = 4π x 10^-7.Thus B = 4π x 10^-7 x 3/2π x 0.12 = 5x 10^-6 units.



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